Al(OH)3 0,2 M sebanyak 100 mL dengan Kb = 2 x 10-5 memiliki pH larutan sebesar ….mohon bantuannya gan November 30, 2021 by Quinn Al(OH)3 0,2 M sebanyak 100 mL dengan Kb = 2 x 10-5 memiliki pH larutan sebesar …. mohon bantuannya gan
Jawaban: Penjelasan: [OH-] = √Kb x [Al(OH)3] = √2 x 10^-5 x 0.2 = √4 x 10^-6 = 2 x 10^-3 pOH = -log [OH-] = -log(2 x 10^-3) = 3 – log2 pH = 14 – pOH = 11 + log2 = 11.301 Reply
Jawaban:
Penjelasan:
[OH-] = √Kb x [Al(OH)3] = √2 x 10^-5 x 0.2 = √4 x 10^-6 = 2 x 10^-3
pOH = -log [OH-] = -log(2 x 10^-3) = 3 – log2
pH = 14 – pOH = 11 + log2 = 11.301