berapa masa kalium hidroksida 50 ml yang mempunyai ph=12 arh=1 ark=39 aro=16 November 30, 2021 by Ella berapa masa kalium hidroksida 50 ml yang mempunyai ph=12 arh=1 ark=39 aro=16
poh = 2 pOH = -log[OH-] 2 = -log10^-2 OH- = 0.01 M KOH > K+ + OH- x. 0.01 1/1 x 0.01 0.01 M 0.01 M = g/mr x 1000/50 0.01 = g/56 x 200 g = 0.01 x 56 / 200 g = 0.0028 g Reply
poh = 2
pOH = -log[OH-]
2 = -log10^-2
OH- = 0.01 M
KOH > K+ + OH-
x. 0.01
1/1 x 0.01
0.01 M
0.01 M = g/mr x 1000/50
0.01 = g/56 x 200
g = 0.01 x 56 / 200
g = 0.0028 g