m=2 kg c=334.000 J/kg Delta T=5 derajat C kalor = November 28, 2021 by Alice m=2 kg c=334.000 J/kg Delta T=5 derajat C kalor =
Jawaban + Penjelasan= Q=m×C× ΔT Q=2 Kg×334.000 J/kg× 5°C Q=10×334.000 Q=3.340.000 J Semoga membantu! Reply
Jawaban + Penjelasan=
Q=m×C× ΔT
Q=2 Kg×334.000 J/kg× 5°C
Q=10×334.000
Q=3.340.000 J
Semoga membantu!