Soal Perbandingan
Tentukan nilai Y:

(4y-8):(2y+1)=4y:(2y+15)​

Jawaban:

3

Penjelasan:

[tex] \frac{4y – 8}{2y + 1} = \frac{4y}{2y + 15} [/tex]

[tex](4y – 8)(2y + 15) = 4y(2y + 1)[/tex]

[tex]8 {y}^{2} + 60y – 16y – 120 = 8 {y}^{2} + 4y[/tex]

[tex]8 {y}^{2} + 44y- 120 = 8 {y}^{2} + 4y[/tex]

[tex]8 {y}^{2} – 8 {y}^{2} + 44y – 4y – 120 = 0[/tex]

[tex]40y – 120 = 0[/tex]

[tex]40y = 120 [/tex]

[tex]y = \frac{120}{40}[/tex]

[tex]y = 3[/tex]

Semoga Membantu