SPLDV METODE ELIMINASI 2×-4y+5=0 dan 4×-6y=2, berapa nilai x dan y?

2x – 4y + 5 = 0 -> 2x – 4y = -5 |×2| 4x – 8y = -10

4x – 6y = 2 |×1 | 4x – 6y = 2 –

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– 2y = -12

y = -12/(-2)

y = 6

4x – 6y = 2

4x – 6(6) = 2

4x – 36 = 2

4x = 2 + 36

4x = 38

x = 38/4 = 19/2

Maka nilai x = 19/2

y = 6